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6063 large-diameter aluminum rod, 540 mm; 6063 aluminum disc, 310mm in diameter; custom-made 6063 aluminum rods. 6063大直径铝棒540mm 6063铝圆盘310mm直径 6063铝棒定做

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XIN HONG Materials Co,.Ltd. 12yr.

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  • Description
brand: 6063
brand: 6063
aluminum content: 91
aluminum content: 91
origin: china
origin: china
item no.: 6063
item no.: 6063
impurity content: 0.000001
impurity content: 0.000001
granularity: 1000
granularity: 1000

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6063 aluminum alloy is widely used in the frames of building aluminum doors, windows, and curtain walls. To ensure that these components have high wind pressure resistance, assembly capability, corrosion resistance, and decorative properties, the requirements for the overall performance of aluminum alloy profiles are far higher than those set by industrial profile standards. Within the composition range specified in the national standard GB/T3190 for 6063 aluminum alloy, different values of chemical components result in different material characteristics. When the range of chemical components is wide, the performance differences can vary significantly, making it difficult to control the overall performance of the profiles.

FoldSelection of content amount

Determination of 2.1Mg2Si Quantity

2.1.1 The role of Mg2Si phase in alloys: In alloys, Mg2Si can dissolve or precipitate with changes in temperature and exist in different forms: (1) Dispersed Mg2Si particles precipitated in the dispersed β'' solid solution are an unstable phase that grow as temperature increases. (2) The transitional phase β' is an intermediate metastable phase formed by the growth of β'', which also grows with increasing temperature. (3) The precipitable phase β is a stable phase formed by the growth of β' phase, often accumulating at grain boundaries and dendritic boundaries. The Mg2Si phase that can enhance strength occurs when it is in the β'' dispersed phase state; the process of converting the β phase into the β'' phase is a strengthening process, while the reverse is a softening process.

2.1.2 Selection of Mg2Si Content: The heat treatment strengthening effect of 6063 aluminum alloy increases with the increase in Mg2Si content. When the Mg2Si content is within the range of 0.71%–1.03%, its tensile strength increases approximately linearly with the amount of Mg2Si, but the deformation resistance also rises, making processing more difficult. However, when the Mg2Si content is less than 0.72%, for products with a small extrusion coefficient (less than or equal to 30), the tensile strength may not meet the standard requirements. When the Mg2Si content exceeds 0.9%, the plasticity of the alloy tends to decrease. According to the GB/T 3237.1–2000 standard, the σb of 6063 aluminum alloy profiles in T5 condition must be ≥160 MPa, and for T6 condition, σb must be ≥205 MPa. Practice has shown that the maximum tensile strength of this alloy can reach 260 MPa. However, there are many factors affecting mass production, and it is impossible to ensure all products meet such high standards. Considering all aspects, the profile should have high strength to ensure compliance with standard requirements, while also being easy to extrude, which helps improve production efficiency. When designing the alloy strength, for profiles delivered in T5 condition, 200 MPa is taken as the design value. As shown in Figure 1, when the tensile strength is around 200 MPa, the Mg2Si content is approximately 0.8%. For profiles in T6 condition, we set the design tensile strength at 230 MPa, resulting in an Mg2Si content of 0.95%.

2.1.3 Determination of Mg Content Once the amount of Mg2Si is determined, the Mg content can be calculated using the following formula: Mg% = (1.73 × Mg2Si%) / 2.73

2.1.4 Determination of Si Content The Si content must meet the requirement that all Mg forms Mg2Si. Since the ratio of relative atomic masses of Mg to Si in Mg2Si is Mg/Si = 1.73, the basic Si amount is SiBase = Mg / 1.73. However, practice has shown that when blending according to SiBase, the produced alloy often has a low tensile strength and fails to meet standards. This is clearly due to an insufficient amount of Mg2Si in the alloy. The reason is that impurity elements such as Fe and Mn in the alloy take up Si; for example, Fe can form ALFeSi compounds with Si. Therefore, there must be excess Si in the alloy to compensate for the loss of Si. The presence of excess Si also helps improve the tensile strength. The increase in tensile strength of the alloy is the sum of contributions from Mg2Si and excess Si. When the Fe content in the alloy is high, Si can further reduce the adverse effects of Fe. However, since Si reduces the ductility and corrosion resistance of the alloy, the amount of excess Si should be properly controlled. Based on practical experience, our factory believes that the amount of excess Si is best within the range of 0.09% to 0.13%. The Si content in the alloy should be: Si% = (SiBase + Excess Si) %


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chemical composition

Silicon Si: 0.20–0.6

Iron Fe: 0.35

Copper Cu: 0.10

Manganese Mn: 0.10

Magnesium Mg: 0.45-0.9

Chromium Cr: 0.10

Zinc Zn: 0.10

Titanium Ti:0.10

Aluminum Al: Remainder

Others:

Single: 0.05 Total: 0.15


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Mechanical properties

Mechanical Properties:

Tensile strength σb (MPa): ≥205

Extended stress σp0.2 (MPa): ≥ 170

Stretch ratio δ5 (%): ≥7

Note: Longitudinal mechanical properties of bars at room temperature

Sample size: diameter ≤ 12.5

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Aluminum alloy weight calculation formula
Editor
Length * Width * Height * Density (0.0028) = kg/m
Radius * Radius * Length * 3.14 * Density (0.0028) = kg/m
 
 
 
 
 
 

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Update time:20261102210206


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